Kindly answer to this question with proper explanation with diagram.
Asked by Varsneya Srinivas | 3rd Oct, 2017, 01:47: PM
This question is from JEE_2013 (Mains). You can refer the following for the solution of the same.
Kindly refer to Question number 68 for the solution. In case you have any doubts in understanding the same, please feel free post your queries.
Answered by Yashvanti Jain | 3rd Oct, 2017, 03:43: PM
- coherent sources
- two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point
- We for equal wave intensities the intensity at a point is given by but where does the formula come from??
- Question 15
- kindly answer
- kindly provide answer pl
- In young double slit experiment, slit with ratio is 3:2 then find out the ratio of the maximum and minimum intensity of interference of light.
- How is phase difference related to path difference?
- In Young's double slit experiment, the distance between the slit is kept smaller than the wavelength of the light. What is the effect?
- Why is Interference pattern not detected when the two coherent sources are far apart?
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