CBSE Class 11-science Answered
To solve this question you can directly apply the formula for distance travelled in nth second.
Sn = u +1/2a(2n-1)
here u, a and n are given.
Say a car is moving with a constant acceleration and you want to find the distance it covers at the end of 4 seconds and till the beginning of the 5th second. It is difficult to visualize because we do not think that a second can be divided into smaller parts. But from 4s to 5s there are 1000 milliseconds.
The above formula is got by taking the distance covered in n seconds and subtracting the distance covered in n-1 seconds.
Displacement and Average VelocityThis video explains the calculation of displacement and average velocity of...
Graphical Representation - 1
Acceleration - Part 1This video explains the graphical representation of distance with a body an...
Kinematics of Linear Motion - 1This video explains the determination of the kinematic equation of linear m...
Average Speed and Average AccelerationThis video explains the calculation of average speed, average acceleration ...