jkk
Asked by saswati509 | 3rd May, 2020, 10:10: AM
Expert Answer:
Given:
Pecentage composition:
C= 40.68%
H= 5.08%
O = 100 - 45.76
O = 54.24%
Empirical formula is C2H3O2
Empirical formula mass : 24+ 3+ 32 = 59
Molecular mass = 2× Vapour density
= 2 ×59 = 118
We konw,
n = 
= 
n = 2
Molecular formula = n × Empirical formula
= 2(C2H3O2)
Molecular formula = C4H6O4
Answered by Varsha | 4th May, 2020, 07:05: PM
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