It is about balls in bags.

Asked by  | 18th Mar, 2008, 10:21: AM

Expert Answer:


Any two balls can be selected from the bag in 12C2 ways

Takig two balls could be first defective second not defective or first not defective but second defective then it can be done in 2* 8C1 * 4C1  

So the probability is 2* 8C1 * 4C1   /12C2 = 32/33

Answered by  | 27th Jun, 2008, 10:40: AM

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