CBSE Class 11-science Answered
is there any proof for De Morgan's law?
Asked by ashwinivg | 25 Jun, 2010, 12:00: AM
Expert Answer
Dear Student
De Morgan laws can be proved as follows
(i) (AUB)' = A' ∩ B'
(i) (AUB)' = A' ∩ B'
Let x 
(AUB)'
(AUB)'So x
(AUB)
(AUB)So x 
A and x B
A and x BSo x A' and x B
A' and x BSo xA'∩B'
A'∩B'So (AUB)' 
A'∩B'
A'∩B'Similarly reversing the steps we can show that A'∩B' (AUB)'
(AUB)'Hope it clarified your answer
Regards
Team Topperlearning
Answered by | 14 Jul, 2010, 03:10: PM
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