Iron (III) nitrate has a solubility of 0.15 M. Find concentration of the ions in solution.
Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM
Fe(NO3)3 → Fe3+(aq) + 3 NO3-(aq)
The concentration of the ions can be determined from the balancing coefficients from the equation:
[Fe3+] = 1× [Fe(NO3)3] = 1 × 0.15 = 0.15 M
[NO3-] = 3× [Fe(NO3)3] = 3 × 0.15 = 0.45 M
Answered by | 4th Jun, 2014, 03:23: PM
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