Iron (III) nitrate has a solubility of 0.15 M. Find concentration of the ions in solution.

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

                                                Fe(NO3)3 Fe3+(aq) + 3 NO3-(aq)
 
The concentration of the ions can be determined from the balancing coefficients from the equation:
 
                                                [Fe3+] = 1× [Fe(NO3)3] = 1 × 0.15 = 0.15 M
 

                        [NO3-] = 3× [Fe(NO3)3] = 3 × 0.15 = 0.45 M

Answered by  | 4th Jun, 2014, 03:23: PM