IOF A,B,C ARE IN A.P. AND 1/B,1/C,1/D ARE IN A.P PROVE THAT AD=BC

Asked by  | 13th Mar, 2012, 10:20: PM

Expert Answer:

Here ,  B-A = C-B , 1/C - 1/B = 1/D - 1/C
So in the second equation we get
(B-C)/BC = (C-D)/CD
(A-B)/BC = (C-D)CD
A/B  - 1 = C/D  - 1
A/B  =  C/D
AD = BC

Answered by  | 14th Mar, 2012, 09:31: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.