Asked by onam singla | 5th Feb, 2012, 12:10: PM

Expert Answer:

sorry, but this integral is not elementary.
In fact, we can reduce it to an elliptic integral.
To see this, let u = sin x, x = sin-1u,
dx = du/root(1-u²)
Then the integral becomes
Integration (root(u) du/root(1-u²)),
and, rationalising the denominator,
Integr (root(u-u³) du/(1-u²))

Since you have the square root of a cubic polynomial
in the integrand, you now have an elliptic integral.
Finally, here is the result from the Wolfram
integrator , a theorem used in Engineering Mathematics for the original problem:

Root sinx cannot be integrated in usual manner ie it's non-integrable.It is an elliptic integral.
Such as 1/(1+(x^2))^(1/3) is also elliptic integral

Answered by  | 6th Feb, 2012, 11:07: AM

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