CBSE Class 12-science Answered
integration
Asked by | 20 Feb, 2010, 08:32: PM
Expert Answer
Put tan-1x = y
x = tany
1 = sec2y dy/dx
1 = (1 + tan2y)dy/dx
1 = (1 + x2)dy/dx
dx/(1+x2) = dy/dx
(earctan x)dx/(1+x2) = eydy = earctan x + c
arctan x = tan-1x
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TopperLearning.
Answered by | 21 Feb, 2010, 06:18: AM
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