integration

Asked by  | 20th Feb, 2010, 08:32: PM

Expert Answer:

Put tan-1x = y

x = tany

1 = sec2y dy/dx

1 = (1 + tan2y)dy/dx

1 = (1 + x2)dy/dx

dx/(1+x2) = dy/dx

(earctan x)dx/(1+x2) = eydy =  earctan x + c

arctan x = tan-1x

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Answered by  | 21st Feb, 2010, 06:18: AM

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