integration
Asked by Kirandoon | 7th Jan, 2009, 02:06: PM
write cos 2x as 1 - 2sin2x so we get numenator of above expression as 2sin2x - (1 - cosx) so the final expression is sin2x / sin2x/2 - 1 (as 1 - cosx = 2 sin2(x/2))
as sin 2a = 2 sin a cos a so sin2x = { 2 sin (x/2) cos (x/2) } 2 = 4 sin 2(x/2) cos2 (x/2)
so final integration term is 4 cos2 (x/2) - 1 = 2(1 + cos x) - 1 = 2cos x + 1
so answer is 2 sinx + x
Answered by | 12th Jan, 2009, 07:59: PM
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