integration
Asked by
| 24th Jan, 2009,
12:59: AM
Expert Answer:
multiply numinator and denominator with undre root sin x and write sin x as 1 - cos 2 x so the final integration is I = sin x / (sin x) = sin x dx /
( 1 - cos 2 x )
now let cos x = t ===> - sinx dx = dt ===> I = - dt / (1 - t 2) ====> I = sin -1 t = - sin -1 (cos x )
Answered by
| 29th Jan, 2009,
05:41: PM
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