integration
Asked by | 24th Jan, 2009, 12:59: AM
Expert Answer:
multiply numinator and denominator with undre root sin x and write sin x as 1 - cos 2 x so the final integration is I = sin x / 
(sin x) = sin x dx / ( 1 - cos 2 x )
now let cos x = t ===> - sinx dx = dt ===> I = - dt / (1 - t 2) ====> I = sin -1 t = - sin -1 (cos x )
Answered by | 29th Jan, 2009, 05:41: PM
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