Integration of trigonometric fn.

Asked by  | 17th Feb, 2009, 07:56: PM

Expert Answer:

multiply cosx in numerator and denominator

then we have sec2x / tanx

now put tanx = t , then sec2x = dt

so we have 1/t  dt = 2t

so answer is 2sinx / cosx

Answered by  | 18th Feb, 2009, 10:06: PM

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