integration of 1/1+e ki power sin x??????
Asked by shashank tripathi
| 20th Jun, 2013,
04:32: AM
Expert Answer:
This question can'e be of indefinite integrals. It should be a question of definite integrals with limits defined from 0 to 2pi.
Then, the solution would be
Let I =limit 0 to 2pi integral 1dx / 1+esinx _______(1)
Now , as limit 0 to a integral f(x)dx = limit 0 to a integral f(a-x)dx
So , I = integral dx /1+e-sinx
I = integral esinx dx / 1+esinx _______(2)
Adding (1) & (2)
2I = limit 0 to 2pi integral (1+esinx)dx /1+esinx
2I = limit 0 to 2pi integral 1dx
2I = limit 0 to 2pi [x]
2I = 2pi 0
I = pi
Let I =limit 0 to 2pi integral 1dx / 1+esinx _______(1)
Now , as limit 0 to a integral f(x)dx = limit 0 to a integral f(a-x)dx
So , I = integral dx /1+e-sinx
I = integral esinx dx / 1+esinx _______(2)
Adding (1) & (2)
2I = limit 0 to 2pi integral (1+esinx)dx /1+esinx
2I = limit 0 to 2pi integral 1dx
2I = limit 0 to 2pi [x]
2I = 2pi 0
I = pi
Answered by
| 20th Jun, 2013,
05:30: AM
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