integrate [x] where lower limit=1,upperlimit=3

Asked by ASEEMA PARVEEN | 24th Nov, 2012, 02:54: PM

Expert Answer:

?[x]dx under lower limit 1 and higher limit3=

As greatest integer remain constant for an integral length,so

For 0?x<1,[x]=0

     1?x<2,[x]=1

    2?x<3,[x]=2

?0dx(0?x<1),+?1dx,(1?x<2),+?2dx(2?x<3)=(2-1)+2(3-2)=3

Answered by  | 26th Nov, 2012, 09:49: AM

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