integrate [x] where lower limit=1,upperlimit=3
Asked by ASEEMA PARVEEN
| 24th Nov, 2012,
02:54: PM
Expert Answer:
?[x]dx under lower limit 1 and higher limit3=
As greatest integer remain constant for an integral length,so
For 0?x<1,[x]=0
1?x<2,[x]=1
2?x<3,[x]=2
?0dx(0?x<1),+?1dx,(1?x<2),+?2dx(2?x<3)=(2-1)+2(3-2)=3
?[x]dx under lower limit 1 and higher limit3=
As greatest integer remain constant for an integral length,so
For 0?x<1,[x]=0
1?x<2,[x]=1
2?x<3,[x]=2
?0dx(0?x<1),+?1dx,(1?x<2),+?2dx(2?x<3)=(2-1)+2(3-2)=3
Answered by
| 26th Nov, 2012,
09:49: AM
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