INTEGRATE X/1-SINX

Asked by Debasish Panigrahi | 18th Feb, 2012, 10:51: AM

Expert Answer:

Rationalize the denominator , that is multiply 1+sinx to num and denominator
we get I = x(1+sinx)/cos2x = x( sec2x + secx.tanx)
Now apply By Parts taking u = x
I = x(tanx+secx) - (log(secx+tanx) + logsecx) ) + C

Answered by  | 18th Feb, 2012, 12:25: PM

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