INTEGRATE THE FOLLOWING FUNCTION

Asked by  | 2nd Nov, 2009, 08:14: AM

Expert Answer:

Put t = 1 + cosx, dt/dx = -sinx; -dt = sinxdx.

Hence, f(x)dx = f(t)dt where f(x)dx = sinxdx/(1+cosx)2 and f(t) = -dt/t2

f(t)dt = -dt/t2 = -t-2dt = -t-2+1/(-2+1) = 1/t = 1/(1+cosx)

Regards,

Team,

TopperLearning.

Answered by  | 2nd Nov, 2009, 11:53: AM

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