integrals

Asked by  | 18th Jan, 2010, 08:37: AM

Expert Answer:

The integral can be evaluated by substituting, cosx = (eix + e-ix)/2, and of the difficulty level which is not expected.

The solution involves polylogarithmic function, Li(s,z).

The solution is,

x2i/2 - xlog(1+e2ix) + xlog cosx + i Li(2,-e2ix) + C

where i = (-1)

Regards,

Team,

TopperLearning.

Answered by  | 18th Jan, 2010, 08:49: PM

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