Integral (sininversex)^2 dx

Asked by rraj.15266 | 5th Dec, 2017, 12:52: PM

Expert Answer:

begin mathsize 16px style integral left parenthesis sin to the power of negative 1 end exponent straight x right parenthesis squared dx
Take space straight u equals left parenthesis sin to the power of negative 1 end exponent straight x right parenthesis squared space and space straight v equals 1
Integrate space by space parts. end style

Answered by Sneha shidid | 5th Dec, 2017, 02:23: PM