CBSE Class 11-science Answered
integral of (sec squarex+secx).dx to the limit 0 to pie/2
Asked by Sindhura K Reddy | 16 Aug, 2010, 09:10: PM
Expert Answer
∫(sec2x + secx) dx =
∫sec2x dx + ∫secx dx = Using standard results,
tanx + ln(secx + tanx) ... now put limits,
= tan π/2 + ln(sec π/2 + tan π/2) - tan 0 + ln(sec 0 + tan 0)
= ∞
Regards,
Team,
TopperLearning.
Answered by | 16 Aug, 2010, 09:57: PM
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