Integral 1/(√1-x^2) sininversex

Asked by rraj.15266 | 27th Nov, 2017, 07:35: AM

Expert Answer:

begin mathsize 16px style integral fraction numerator 1 over denominator square root of 1 minus straight x squared end root end fraction sin to the power of negative 1 end exponent xdx
Put space sin to the power of negative 1 end exponent straight x equals straight t
fraction numerator 1 over denominator square root of 1 minus straight x squared end root end fraction dx equals dt
integral tdt
Integrate space it space further. end style

Answered by Sneha shidid | 28th Nov, 2017, 05:05: PM