indices

Asked by  | 25th Jul, 2009, 07:17: AM

Expert Answer:

 

(p+q)-1(p-1+q-1)=paqb

(1/p+q)(p+q/pq)=paqb

pa+1qb+1 =p0q0

a+1=0 , b+1=0

a+b+2=0

 

 

 

Answered by  | 30th Jul, 2009, 12:26: AM

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