indices
Asked by | 25th Jul, 2009, 07:17: AM
Expert Answer:
(p+q)-1(p-1+q-1)=paqb
(1/p+q)(p+q/pq)=paqb
pa+1qb+1 =p0q0
a+1=0 , b+1=0
a+b+2=0
Answered by | 30th Jul, 2009, 12:26: AM
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