In young's double slit experiment,using light of wavelength 400nm,interference fringes of width 'X' are obtained.The wavelength of light is increased to 600nm and the separation between the slits is halved.If one wants observed fringe width on the screen to be same in the two cases,find the ratio of distance between the screen and the plane of the interfering sources in the two arrangements?

Asked by SUHAS MELMURI | 14th Nov, 2013, 05:23: AM

Expert Answer:

Answered by Faiza Lambe | 14th Nov, 2013, 12:06: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.