in triangle abc,if AD is the median,show that AB SQUARE + AC SQUARE = 2(AD SQUARE + BD SQUARE)

Asked by  | 18th Sep, 2013, 11:52: AM

Expert Answer:

Draw AE perpendicular to BC.

Since angle AED = 900,

Therefore, in triangle ADE

 angle ADE < 900 and angle ADB > 900

Thus, triangle ABD is obtuse angled triangle and triangle ADC is acute angled triangle.

Triangle ABD is obtuse angled at D and AE is perpendicular to BD produced,

Therefore,

AB2 = AD2 + BD2 + 2 BD x DE ……………(i)

Triangle ACD is acute angled at D and AE is perpendicular to BD produced,

Therefore,

AC2 = AD2 + DC2 - 2 DC x DE

 AC2 = AD2 + BD2 - 2 BD x DE  ………(ii)        (since CD = BD)

Adding (i) and (ii)

AB2 + AC2 = 2AD2 + 2BD2

AB2 +AC2 = 2(AD2 + BD2)

 

Answered by  | 18th Sep, 2013, 03:12: PM

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