CBSE Class 10 Answered
In triangle ABC, D is the mid-point of BC and AE
BC. If AC > AB. Show that: AB2 = AD2 - BC x DE + 
BC. If AC > AB. Show that: AB2 = AD2 - BC x DE +
Asked by Topperlearning User | 22 Dec, 2014, 13:30: PM
Expert Answer
AD is the median of triangle ABC, since D is mid-point of BC.
BD = DC= 
....(i)
In right triangle AEB,
(Pythagoras theorem)
AB2 = (
)+ 
(By using Pythagoras theorem for right triangle AED and BE = BD - DE)
AB2 =+
....from (i)
AB2 =+
+ 
-2 
-BC x DE +
Hence proved.
Answered by | 22 Dec, 2014, 15:30: PM
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