CBSE Class 10 Answered
In triangle ABC, D is the mid-point of BC and AE
BC. If AC > AB. Show that: AB2 = AD2 - BC x DE + 
BC. If AC > AB. Show that: AB2 = AD2 - BC x DE +
Asked by Topperlearning User | 22 Dec, 2014, 01:30: PM
Expert Answer
AD is the median of triangle ABC, since D is mid-point of BC.
BD = DC= 
....(i)
In right triangle AEB,
(Pythagoras theorem)
AB2 = (
)+ 
(By using Pythagoras theorem for right triangle AED and BE = BD - DE)
AB2 =+
....from (i)
AB2 =+
+ 
-2 
-BC x DE +
Hence proved.
Answered by | 22 Dec, 2014, 03:30: PM
CBSE 10 - Maths
Asked by shivalaxmi0205 | 11 Mar, 2024, 05:51: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by mishraananya969 | 05 Mar, 2024, 11:23: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by surender0145 | 07 Jan, 2024, 08:59: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by darshanpatilr08 | 19 Sep, 2023, 10:35: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by supriyasupriya39.10 | 20 Jan, 2023, 08:40: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by savitamahajan202 | 29 Dec, 2022, 02:12: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by Topperlearning User | 22 Dec, 2014, 01:30: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by | 03 Dec, 2012, 12:06: AM
ANSWERED BY EXPERT
