In the figure, ABCD and EFGD are 2 parallelograms and G is the midpoint of CD. Then prove that ar(triangle DPC)= 1/2 ar(parallelogram EFGD)
Asked by Sthitaprajna Mishra
| 9th Feb, 2014,
02:44: PM
Expert Answer:
Answered by
| 10th Feb, 2014,
03:18: PM
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