In the figure, ABCD and EFGD are 2 parallelograms and G is the midpoint of CD. Then prove that ar(triangle DPC)= 1/2 ar(parallelogram EFGD)

Asked by Sthitaprajna Mishra | 9th Feb, 2014, 02:44: PM

Expert Answer:

Answered by  | 10th Feb, 2014, 03:18: PM

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