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In the circuit shown in fig ,the reading of ammeter A is  
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Asked by matamshanthireddy141 | 28 May, 2021, 03:31: PM
answered-by-expert Expert Answer
Given circuit is redrawn and given as fig.(1) to show that the resistances 3Ω, 2Ω and 6Ω are in parallel .
 
Equivalent Resistance R of these three resistances is given as
 
(1/R) = ( 1/3 ) + ( 1/2 ) + ( 1/6) 
 
we get R = 1Ω from above equation .
 
In fig.(2) , we replace three resistances by 1Ω and calculate the current I  in the circuit
 
I = Voltage / Resistance = 2 V / ( 4 + 1 ) Ω = 0.4 A 
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