JEE Class main Answered
In the circuit shown in fig ,the reading of ammeter A is
Asked by matamshanthireddy141 | 28 May, 2021, 15:31: PM
Expert Answer
Given circuit is redrawn and given as fig.(1) to show that the resistances 3Ω, 2Ω and 6Ω are in parallel .
Equivalent Resistance R of these three resistances is given as
(1/R) = ( 1/3 ) + ( 1/2 ) + ( 1/6)
we get R = 1Ω from above equation .
In fig.(2) , we replace three resistances by 1Ω and calculate the current I in the circuit
I = Voltage / Resistance = 2 V / ( 4 + 1 ) Ω = 0.4 A
Answered by Thiyagarajan K | 28 May, 2021, 16:17: PM
Concept Videos
-
Combination of Cells - Part 1
This video describes about the working of cells in series combination.
JEE main - Physics
Asked by ratchanavalli07 | 17 Sep, 2024, 07:46: AM
ANSWERED BY EXPERTJEE main - Physics
Asked by arivaryakashyap | 23 Apr, 2024, 10:40: AM
ANSWERED BY EXPERTJEE main - Physics
Asked by avneetsingh09 | 09 Mar, 2024, 13:18: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by yuvarajgududuru | 30 Oct, 2023, 09:32: AM
ANSWERED BY EXPERTJEE main - Physics
Asked by aaryamanmodern | 21 Aug, 2023, 10:43: AM
ANSWERED BY EXPERTJEE main - Physics
Asked by aaryamanmodern | 22 Jun, 2023, 15:10: PM
ANSWERED BY EXPERTJEE main - Physics
Asked by ojasgarg96 | 26 Dec, 2022, 09:55: AM
ANSWERED BY EXPERTJEE main - Physics
Asked by ojasgarg96 | 25 Dec, 2022, 22:10: PM
ANSWERED BY EXPERTJEE main - Physics
Asked by ojasgarg96 | 25 Dec, 2022, 10:26: AM
ANSWERED BY EXPERT