In the circuit shown in fig ,the reading of ammeter A is
Asked by matamshanthireddy141 | 28th May, 2021, 03:31: PM
Given circuit is redrawn and given as fig.(1) to show that the resistances 3Ω, 2Ω and 6Ω are in parallel .
Equivalent Resistance R of these three resistances is given as
(1/R) = ( 1/3 ) + ( 1/2 ) + ( 1/6)
we get R = 1Ω from above equation .
In fig.(2) , we replace three resistances by 1Ω and calculate the current I in the circuit
I = Voltage / Resistance = 2 V / ( 4 + 1 ) Ω = 0.4 A
Answered by Thiyagarajan K | 28th May, 2021, 04:17: PM
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