In the circuit shown in fig ,the reading of ammeter A is

 

Asked by matamshanthireddy141 | 28th May, 2021, 03:31: PM

Expert Answer:

Given circuit is redrawn and given as fig.(1) to show that the resistances 3Ω, 2Ω and 6Ω are in parallel .
 
Equivalent Resistance R of these three resistances is given as
 
(1/R) = ( 1/3 ) + ( 1/2 ) + ( 1/6) 
 
we get R = 1Ω from above equation .
 
In fig.(2) , we replace three resistances by 1Ω and calculate the current I  in the circuit
 
I = Voltage / Resistance = 2 V / ( 4 + 1 ) Ω = 0.4 A 

Answered by Thiyagarajan K | 28th May, 2021, 04:17: PM