In square ABCD,P and Q are mid points of AB and CD resp.If AB=8cm and PQ and BD intersect at O,then find the area of triangle OPB.
Asked by | 13th Jan, 2013, 12:28: PM
P and Q are mid points of AB and CD respectively.
So, PQ is parallel to AC.
=> OP is parallel to AC.
Hence, OP = 1/2 AC = 1/2 * 8 = 4 cm [Side of square is given as 8 cm]
ar(triangle OPB) = 1/2 * PB * OP = 1/2 * 4 cm * 4 cm = 8 cm2
Answered by | 7th Feb, 2013, 02:07: PM
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