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In quadrilateral ABCD; P,Q,R and S are points of trisection of sides AB, BC, CA and AD. Prove PQRS is a Parallelogram.   In the solution of this question shown in the video(exam decoded of converse of BPT section), its shown that : BP = 2AP, BQ = 2QC, DR = 2RC and DS = 2SA. explain this step in detail that how is this possible
Asked by Trisha Gupta | 07 Sep, 2021, 07:04: PM
answered-by-expert Expert Answer
As P is the point of trisection of AB, we get
AP over PB equals 1 half rightwards double arrow PB equals 2 AP
 
As Q is the point of trisection of BC, we get
BQ over QC equals 1 half rightwards double arrow QC equals 2 BQ
 
Similarly, 
CR over RD equals 1 half space and space DS over SA equals 1 half rightwards double arrow RD equals 2 CR space and space SA equals 2 DS
Answered by Renu Varma | 09 Sep, 2021, 12:13: AM

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CBSE 10 - Maths
In quadrilateral ABCD; P,Q,R and S are points of trisection of sides AB, BC, CA and AD. Prove PQRS is a Parallelogram.   In the solution of this question shown in the video(exam decoded of converse of BPT section), its shown that : BP = 2AP, BQ = 2QC, DR = 2RC and DS = 2SA. explain this step in detail that how is this possible
Asked by Trisha Gupta | 07 Sep, 2021, 07:04: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
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