ICSE Class 10 Answered
In quadratic equation how to solve each of the following equation (2x+3)2=81
Asked by josephjo3333 | 05 Mar, 2019, 01:15: PM
Expert Answer
(2x+3)2 = 81
4x2 + 12x + 9 = 81
4x2 + 12x - 72 = 0
Dividing on both the sides of the above equation by 4,
x2 + 3x - 18 = 0
x2 + 6x - 3x -18 = 0
x (x+6) -3 (x+6) = 0
(x+6) or (x-3) =0
x = -6 or x = 3
Answered by Science Mate | 05 Mar, 2019, 02:29: PM
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