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In order to determine the molecular weight of a particular protein,0.01g of the protein was dissolved in water to make 2.93mL of solution. The osmotic pressure was determined to be 0.821 torr 20.00c at . What is the molecular weight of the protein?

Asked by s.ojaswini17 | 05 Feb, 2019, 02:29: AM
Expert Answer
Given:
 
Weight of protein = 0.01 g
 
Volume of solution = 2.93 ml 
 
                            =2.93× 10-3 litre
 
Osmoti pressure Π = 0.821 torr
 
                           = 0.00108 atm
 
Temperature T = 20 °C
 
                      = 20 + 273 
 
                      =293 K
 
Molecular weight of the protein  M =?
 
R = 0.0821 litatmmol-1K-1
 
We know,
 
Molecular weight  = 
 
 
straight M space equals WRT over πV

space space space space equals fraction numerator 0.01 cross times 0.0821 cross times 293 over denominator 0.001 cross times 2.93 space cross times space 10 to the power of negative 3 end exponent end fraction

space space space space equals fraction numerator 0.241 over denominator 293 cross times space 10 to the power of negative 5 end exponent end fraction

space space space equals 82300 space straight g divided by mol 
 
Molecular weight of protein is 82300 g/mol
 
Answered by Varsha | 05 Feb, 2019, 11:58: AM
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