in NCERT misslaneous 5 question 7 without using log can we do
i want all log formulae
thank u

Asked by devsingh71 | 22nd May, 2014, 08:47: PM

Expert Answer:

C o n s i d e r space y equals open parentheses log x close parentheses to the power of log x end exponent T a k i n g space log a r i t h m s space o n space b o t h space t h e space s i d e s comma space w e space h a v e log y equals log open square brackets open parentheses log x close parentheses to the power of log x end exponent close square brackets rightwards double arrow log y equals log x cross times log open square brackets open parentheses log x close parentheses close square brackets D i f f e r e n t i a t i n g space b o t h space t h e space s i d e s space comma space w e space h a v e 1 over y cross times fraction numerator d y over denominator d x end fraction equals log x cross times fraction numerator 1 over denominator log x end fraction cross times 1 over x plus fraction numerator log open square brackets open parentheses log x close parentheses close square brackets over denominator x end fraction rightwards double arrow fraction numerator d y over denominator d x end fraction equals open parentheses log x close parentheses to the power of log x end exponent cross times 1 over x plus open parentheses log x close parentheses to the power of log x end exponent cross times fraction numerator log open square brackets open parentheses log x close parentheses close square brackets over denominator x end fraction rightwards double arrow fraction numerator d y over denominator d x end fraction equals open parentheses log x close parentheses to the power of log x end exponent open square brackets 1 over x plus fraction numerator log open square brackets open parentheses log x close parentheses close square brackets over denominator x end fraction close square brackets

Answered by Vimala Ramamurthy | 23rd May, 2014, 11:34: AM