In NCERT book Ex 7.2 question no.5 I am unable to understand that sin2(ax+b)/2.then we take 2(ax+b)=t but 2adx = dt How and from where the 'a' comes.please explain

Asked by Abhishek Poonia | 5th Nov, 2012, 09:34: AM

Expert Answer:

We can write sin (ax+ b) cos (ax + b) as sin2(ax+ b)/ 2.
(By using the formula sin 2A = 2 sin A cos A)
Now, we substitute 2(ax + b) = t
So, 2ax + 2b = t
Differentiating both sides, we get:
2a dx = dt
Now, with this substitution, we can easily integrate the given function.

Answered by  | 5th Nov, 2012, 11:22: AM

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