In how many ways can the letters of the word "PERMUTATIONS" be arranged if there are always 4 letters between P and S?
Asked by sumukhverma1107 | 2nd Oct, 2010, 12:00: AM
Folowing is the solution to your question
Consider letter PERMUTATIONS, there are 12 letters
Put 12 dashes: 1 2 3 4 5 6 7 8 9 10 11 12 and number them as done.
Now select 6 consecutive dashes, like if we consider 2nd place till 7th place, on 2nd place and seventh place P and S can be placed and in between 4 places are left.
We can select these consecutive place in 7 ways i.e. 1-6 and 2-7 and 3-8 and so on and multiply by 2! as they can be P and S can interchange their positions
Total ways for P and S= 7x2!
Corrosponding to these ways we can place the other 10 digits in 10 places as
therefore ans = = 25401600
Answered by | 4th Oct, 2010, 08:51: PM
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