In how many ways, a party of 5 men and 5 women be seated at a circular table, so that no two women are adjacent?
Asked by rksvikhyat | 17th May, 2012, 01:19: PM
The 5 men can be seated at the circular table such that there is a vacant seat between every pair of men.
The number of ways in which these men can be seated = 4! = 24 ways.
Now, the 5 vacant seats may be occupied by 5 women in 5! = 120 ways
Therefore, the required number of ways = (24 x 120) = 2880 ways.
Answered by | 18th May, 2012, 10:08: AM
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