In HCl molecule, the separation between the nuclei of the H and Cl atom is 1.27 angstrom. If the mass of of Cl atom is 35.5 times of H atom , then obtain the centre of mass of the molecule.

Asked by s_patne2002 | 25th Nov, 2015, 11:49: AM

Expert Answer:

begin mathsize 12px style Let comma space straight x space be space the space mass space of space the space hydrogen space atom Consider space the space hydrogen space atom space is space located space at space straight x subscript 1 space equals space 0 and space chlorine space atom space of space mass space 35.5 space straight m space is space located space at space straight x subscript 2 space equals space 1.27 space cross times space 10 to the power of negative 10 end exponent space straight m Let space straight X space be space the space distance space of space the space centre space of space mass space of space HCL space molecule straight X space equals space fraction numerator left parenthesis straight m subscript 1 straight x subscript 1 space plus space straight m subscript 2 straight x subscript 2 right parenthesis over denominator open parentheses straight m subscript 1 space plus space straight m subscript 2 close parentheses end fraction straight X space equals space fraction numerator left parenthesis 0 space plus space left square bracket 35.5 space cross times space 1.27 space cross times space 10 to the power of negative 10 end exponent right square bracket over denominator open parentheses 1 space plus space 35.5 close parentheses end fraction space equals space 1.235 space cross times space 10 to the power of negative 10 end exponent space straight m therefore space straight X space equals space 1.235 space straight A degree end style

Answered by Priyanka Kumbhar | 25th Nov, 2015, 03:18: PM

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