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CBSE Class 9 Answered

<div> <div>.<span style="white-space: pre;"> </span>In<span style="white-space: pre;"> </span>free<span style="white-space: pre;"> </span>fall<span style="white-space: pre;"> </span>of<span style="white-space: pre;"> </span>objects<span style="white-space: pre;"> </span>the<span style="white-space: pre;"> </span>acceleration<span style="white-space: pre;"> </span>in<span style="white-space: pre;"> </span>velocity<span style="white-space: pre;"> </span>due<span style="white-space: pre;"> </span>to<span style="white-space: pre;"> </span>gravity<span style="white-space: pre;"> </span>is<span style="white-space: pre;"> </span>independent<span style="white-space: pre;"> </span>of<span style="white-space: pre;"> </span>mass of<span style="white-space: pre;"> </span>those<span style="white-space: pre;"> </span>objects<span style="white-space: pre;"> </span>hence<span style="white-space: pre;"> </span>a<span style="white-space: pre;"> </span>heavy<span style="white-space: pre;"> </span>object<span style="white-space: pre;"> </span>does<span style="white-space: pre;"> </span>not<span style="white-space: pre;"> </span>fall<span style="white-space: pre;"> </span>faster<span style="white-space: pre;"> </span>than<span style="white-space: pre;"> </span>alight<span style="white-space: pre;"> </span>object. Why?</div> </div> <div>&nbsp;</div>
Asked by dhruvtyagi1001 | 22 Oct, 2017, 09:41: PM
Expert Answer
begin mathsize 12px style A c c e l e r a t i o n space d u e space t o space g r a v i t y space i s space g i v e n space b y space g space equals space fraction numerator G M over denominator R squared end fraction end style . Where G is gravitational constant, M mass of earth and R is radius of earth.
Hence accleration due to gravity is independent of mass of falling object. So heavy object does not fall faster than light object.
Answered by | 23 Oct, 2017, 10:28: AM

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