In expansion of (1+x)to power 14 write the coefficient of x to the power 5?
Asked by SHRUTI GUPTA | 19th Oct, 2013, 05:34: PM
Tr+1 is general term in the expansion of (1+x)14.
Tr+1 = 14Cr x14-r (1)r = 14Cr x14-r
x5 occurs in it, if 14 - r = 5 or r = 9
Tr+1 = 14C9 x14-9 = 14C9 x5
Thus, the coefficient of x5 is 14C9
Answered by | 19th Oct, 2013, 07:32: PM
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