In any triangle ABC,if a=18,b=24,c=30. find sin A , sin B , sin C

Asked by Aashna Anith Kumar | 24th May, 2013, 03:12: PM

Expert Answer:

The triangle sides given is a pythogarian triplet as 18^2 +24^2=324+576=900=30^2
 
Thus angle C =90
thus sinC=1
sinA= 18/30 =3/5
sinB=24/30=4/5

Answered by  | 25th May, 2013, 10:03: PM

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