CBSE Class 10 Answered
In an A.P sum of the first 2 term is 5 and sum of the last 2 term is 129. Then find the sequence
Asked by dhruthanmn | 06 Jun, 2020, 03:35: PM
According to the question,
a + (a+d) = 5
2a + d = 5 .... (i)
a+(n-2)d+a+(n-1)d=129
2a + d(2n-3) = 129 ... (ii)
Subtracting (i) from (ii), we get
d(2n-4) = 124
d(n-2) = 62
n = 62/d + 2
Since n has to be a non-zero positive integer.
Therefore, d can take the values 1, 2, 31 or 62
Basis on this, find the value of a and hence the sequence.
Answered by Renu Varma | 06 Jun, 2020, 09:07: PM
Application Videos
Concept Videos
CBSE 10 - Maths
Asked by bkhaiwangkonyak | 07 Mar, 2023, 04:35: PM
CBSE 10 - Maths
Asked by sakshinde95 | 23 Jan, 2023, 05:50: PM
CBSE 10 - Maths
Asked by d7016880266 | 20 Jan, 2023, 08:14: PM
CBSE 10 - Maths
Asked by jaiprakashprasadr | 17 Jul, 2022, 11:03: PM
CBSE 10 - Maths
Asked by Keerthanaambika48 | 13 Jul, 2021, 09:44: AM
CBSE 10 - Maths
The sum of the first 7 terms of an A.P is 182 if its 4th ans 17th terms are in ratio 1:5 find the Ap
Asked by madhutowari | 28 Jun, 2021, 07:56: PM
CBSE 10 - Maths
Asked by maulaali35 | 24 Oct, 2020, 08:00: AM
CBSE 10 - Maths
Asked by Anubhavjain599 | 25 Aug, 2020, 10:16: PM
CBSE 10 - Maths
Asked by seeni2005 | 17 Aug, 2020, 12:42: AM
CBSE 10 - Maths
Asked by Deepakaryan571 | 09 Aug, 2020, 12:18: PM