CBSE Class 9 Answered
In a triangleABC,AD is a median on BC&AE is perpendicular toBC.Prove thtAB.AB=AD.AD-BC.DE+1/4BC.BC
Asked by | 04 Mar, 2008, 06:01: PM
Given:-In the adjoining figure D is mid point of side BC of Triangle ABC and AD is the median from A to side BC .and AE is the perpendicular drawn from A to BC.
To Prove:-AB2 = AD2 – BC.DE + ¼ BC2
Proof:- AB2 = AE2 + BE2
AB2 = AD2 – ED2 + (BD –ED)2
AB2 = AD2 – ED2 + BD2 + ED2 -2*BD*ED
AB2 = AD2 – 2*BC/2 * DE + (1/2 BC)2
AB2 = AD2 – BC * DE + 1/4 BC2
Answered by | 01 Jul, 2008, 10:38: PM
Application Videos
Concept Videos
CBSE 9 - Maths
Asked by Krishna962511 | 23 Jan, 2023, 10:41: AM
CBSE 9 - Maths
Asked by kandalashyamala20 | 27 Dec, 2022, 02:30: PM
CBSE 9 - Maths
Asked by sumitrasangwa041 | 02 Jul, 2022, 02:21: PM
CBSE 9 - Maths
Asked by bathinisampath | 05 Apr, 2022, 10:50: AM
CBSE 9 - Maths
Asked by shivendrasinghfauzdar | 09 Oct, 2021, 11:30: AM
CBSE 9 - Maths
Asked by arahant2008 | 07 Oct, 2021, 09:38: PM
CBSE 9 - Maths
Asked by thebeatinbrat | 01 Oct, 2021, 08:56: PM
CBSE 9 - Maths
Asked by abdulsamad82007 | 15 Jun, 2021, 12:59: PM
CBSE 9 - Maths
Asked by rjaat7623 | 28 Feb, 2021, 10:57: AM