Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 9 Answered

In a triangleABC,AD is a median on BC&AE is perpendicular toBC.Prove thtAB.AB=AD.AD-BC.DE+1/4BC.BC
Asked by | 04 Mar, 2008, 06:01: PM
Expert Answer

 

 

 

 

                          

Given:-In the adjoining figure D is mid point of side BC of Triangle ABC and AD is the median from A to side BC .and AE is the perpendicular drawn from A to BC.

 

To Prove:-AB2 = AD2 – BC.DE + ¼ BC2   

 

Proof:- AB2 = AE2 + BE2

            AB2 = AD2 – ED2 + (BD –ED)2

            AB2 = AD2 – ED2 + BD2 + ED2 -2*BD*ED

            AB2 = AD2 – 2*BC/2 * DE + (1/2 BC)2

            AB2 = AD2 – BC * DE + 1/4 BC2

 

Answered by | 01 Jul, 2008, 10:38: PM
CBSE 9 - Maths
Asked by sumitrasangwa041 | 02 Jul, 2022, 02:21: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by bathinisampath | 05 Apr, 2022, 10:52: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by bathinisampath | 05 Apr, 2022, 10:50: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by shivendrasinghfauzdar | 09 Oct, 2021, 11:30: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by thebeatinbrat | 01 Oct, 2021, 08:56: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by abdulsamad82007 | 15 Jun, 2021, 12:59: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by rjaat7623 | 28 Feb, 2021, 10:57: AM
ANSWERED BY EXPERT
Season Break Offer!
Get 60% Flat off instantly.
Avail Now
×