In a triangle ABC, E and F are the mid points of AB and AC respectively. The altitude AP to BC intersects FE at Q.Prove that AQ = QP.

Asked by  | 5th Feb, 2012, 10:46: PM

Expert Answer:

Since E ,F are the mid points of AB and BC so , By mid point Theorem,
EF || BC , EF = 1/2 BC
Now In Triangle ABP
Since E is the mid point of AB , EQ || BP , So by Converse of mid point theorem
Q is the mid point of AP
AQ = QP

Answered by  | 6th Feb, 2012, 01:49: PM

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