Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

In a system of units, let the units of force energy and velocity be 10 N,0.1 J and 100 m/s respectively. In this new system find the unit of length,mass and time
 
Asked by Anil | 21 May, 2017, 09:27: PM
answered-by-expert Expert Answer
begin mathsize 12px style Let space straight M subscript 1 space comma space straight L subscript 1 space space and space straight T subscript 1 space space be space the space units space of space mass comma space length space and space time space in space SI space and straight M subscript 2 space comma straight L subscript 2 space space and space straight T subscript 2 space space the space corresponding space units space in space new space system. Dimensional space formula space for space force space is space open square brackets straight M to the power of 1 space straight L to the power of 1 space straight T to the power of – 2 end exponent close square brackets rightwards arrow Conversion space formula space for space force space becomes straight n subscript 2 space space equals space straight n subscript 1 space open square brackets straight M subscript 1 over straight M subscript 2 close square brackets to the power of 1 space open square brackets straight L subscript 1 over straight L subscript 2 close square brackets to the power of 1 space open square brackets straight T subscript 1 over straight T subscript 2 close square brackets to the power of negative 2 end exponent Given space that space here space straight n subscript 1 space equals space 10 space straight N space and space straight n subscript 2 space equals space 1 therefore space 1 space space equals space 10 space open square brackets straight M subscript 1 over straight M subscript 2 close square brackets to the power of 1 space open square brackets straight L subscript 1 over straight L subscript 2 close square brackets to the power of 1 space open square brackets straight T subscript 1 over straight T subscript 2 close square brackets to the power of negative 2 end exponent space space......... space left parenthesis Equation space 1 right parenthesis Dimensional space formula space for space work space is space open square brackets straight M to the power of 1 space straight L squared space straight T to the power of – 2 end exponent close square brackets rightwards arrow Conversion space formula space for space energy space becomes straight n subscript 2 space space equals space straight n subscript 1 space open square brackets straight M subscript 1 over straight M subscript 2 close square brackets to the power of 1 space open square brackets straight L subscript 1 over straight L subscript 2 close square brackets squared space open square brackets straight T subscript 1 over straight T subscript 2 close square brackets to the power of negative 2 end exponent Given space that space here space straight n subscript 1 space equals space 5 space straight J space and space straight n subscript 2 space equals space 1 1 space space equals space 5 space open square brackets straight M subscript 1 over straight M subscript 2 close square brackets to the power of 1 space open square brackets straight L subscript 1 over straight L subscript 2 close square brackets squared space open square brackets straight T subscript 1 over straight T subscript 2 close square brackets to the power of negative 2 end exponent space space......... space left parenthesis Equation space 2 right parenthesis Dimensional space formula space for space velocity space is space open square brackets straight M to the power of 0 space straight L to the power of 1 space straight T to the power of – 1 end exponent close square brackets rightwards arrow Conversion space formula space for space velocity space becomes straight n subscript 2 space space equals space straight n subscript 1 space open square brackets straight M subscript 1 over straight M subscript 2 close square brackets to the power of 0 space open square brackets straight L subscript 1 over straight L subscript 2 close square brackets to the power of 1 space open square brackets straight T subscript 1 over straight T subscript 2 close square brackets to the power of negative 1 end exponent Given space that space here space straight n subscript 1 space equals space 0.5 space straight J space and space straight n subscript 2 space equals space 1 1 space space equals space 0.5 space open square brackets straight L subscript 1 over straight L subscript 2 close square brackets to the power of 1 space open square brackets straight T subscript 1 over straight T subscript 2 close square brackets to the power of negative 1 end exponent space......... space left parenthesis Equation space 3 right parenthesis Dividing space equation space left parenthesis 2 right parenthesis space by space space equation space left parenthesis 1 right parenthesis comma space we space get straight L subscript 2 space equals space straight L subscript 1 over 2 space equals space 1 half space straight m space equals space 0.5 space straight m therefore straight L subscript 1 over straight L subscript 2 space equals space 2 Substituting space this space value space in space equation space left parenthesis 3 right parenthesis comma space we space get 1 space space equals space 0.5 space cross times space 2 space cross times space open square brackets straight T subscript 1 over straight T subscript 2 close square brackets to the power of negative 1 end exponent rightwards arrow straight T subscript 1 over straight T subscript 2 space equals space 1 therefore space straight T subscript 2 space equals space 1 straight s Substituting space this space value space of space open square brackets straight L subscript 1 over straight L subscript 2 close square brackets space and space open square brackets straight T subscript 1 over straight T subscript 2 close square brackets space in space equation space left parenthesis 1 right parenthesis comma space we space get 1 space space equals space 10 space open square brackets straight M subscript 1 over straight M subscript 2 close square brackets to the power of 1 space cross times space 2 space cross times space 1 space rightwards arrow space 1 space equals space 20 open square brackets straight M subscript 1 over straight M subscript 2 close square brackets rightwards arrow straight M subscript 2 space equals space 20 space straight M subscript 1 As space straight M subscript 1 space equals space 1 space kg therefore space straight M subscript 2 space equals space 20 space kg space Hence space units space of space mass comma space length space and space time space are space 20 space kg comma space 0.5 space straight m space and space 1 space sec space respectively. end style
Answered by Yashvanti Jain | 22 May, 2017, 12:00: PM

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
CBSE 11-science - Physics
the dimension of stopping potential vo in photoelectric effect in units of plank's constant 'h',speed of light 'c' and gravitational constant 'G' and ampereA
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
In physics if 2 quantities are dimensionless then their dimensional formula are equal?
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
frequency of vibration (n) of a stretched string depends on its length (l) , tension (t) and linear mass density taking proportionality constant k=½ find a relation between them
Asked by ss4172380 | 14 Nov, 2023, 08:05: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Calculate the wave number of a wave with a frequency of 6.2 *10^7
Asked by doddisriman | 29 Oct, 2023, 09:43: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
The respective number of significant figures for the numbers 23.023; 0.0003 and 2.1´10-3 are (a) 4, 4, 2                     (b) 5, 1, 2                     (c) 5, 1, 5                     (d) 5, 5, 2
Asked by Naveensharma2007 | 26 Jun, 2023, 06:54: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
signify digit of 0.7048
Asked by manthansakhare050 | 18 Dec, 2022, 01:54: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
For class 12 physics cbse board will they ask us dimensional formula for anything?will there be questions expected as to write the dimensional formulas?  
Asked by adibafatima2004 | 11 Sep, 2021, 08:02: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
if the unit of length and mass be doubled then the numerical value of w. r. t present value of universal gravitational constant will become
Asked by suhani.pare | 28 Jun, 2021, 09:03: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
check the dimensional accuracy of n=1/2L*rootT/M
Asked by gopikagopakumar43 | 13 Dec, 2020, 12:56: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
plzz solve this my que
question image
Asked by sagarrc1564 | 11 Sep, 2020, 01:33: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×