In a square ABCD, its diagonals AC and BD intersect each other at point O. The bisectors of angle DAO meets BD at point M and the bisector of angle ABD meets AC at N and AM at L. Show that:\n(i)angle ONL+ angle OML =180 degree. \n(ii) angle BAM =angle BMA.\n (iii)ALOB is a cyclic quadrilateral.
Asked by SANKALP | 2nd Oct, 2015, 11:57: AM
Expert Answer:



Answered by Priti Shah | 5th Oct, 2015, 12:07: PM
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