In a solid having FCC structure oxide ions constitutes lattice points of the solid if divalent cation (A2+) occupys 25% of octahedral void and trivalent cation (B3+) occupy 12.5% of the tetrahedral void ,then what is the formula of solid?

Asked by DIPTI PRIYA | 4th Mar, 2011, 11:47: PM

Expert Answer:

Lattice points=No. of atoms in crystal
No. of Octahedral void =No. of lattice sites
No. of tetrahedral voids= 2. No. of lattice sites
 
Let us consider The lattice sites (O-2)=x
No. of octaherdal Voids (A+2)=x.25/100
No. of tetrahedral Voids (B+3)=2x.12.5/100
 
x: x.25/100: 2x.12.5/100
x:x/4:x/4
Hence the formulais
ABO4

Answered by  | 5th Mar, 2011, 12:37: PM

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