CBSE Class 9 Answered
In a quadrilateral ABCD bisectors of angle A and angle B meet at O. Prove that angle AOB =1/2(
Asked by masara | 04 Dec, 2009, 09:58: PM
Expert Answer
Sum of the angles of a quadrilateral is 360
so 
A+B+C+D = 360
C+D = 360 -A+B = 2(180 - (A+B )/2) ---(i)
Also in triagle AOB
AOB+ABO+BAO = 180
AOB + 1/2(A+B ) =180
AOB = 180 - 1/2(A+B ) -------(ii)
from (i) and (ii)
we have AOB =1/2 ( C+D )
Answered by | 05 Dec, 2009, 10:26: AM
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