In a parallelogram ABCD, E and F are the points on AB and CD such that AE=CE. Prove that ED is parallel to BF
Asked by | 17th Nov, 2013, 07:37: PM
Given: ABCD is a parallelogram and AE = CF ...(1)
To Prove: EDBF
Since the opposite sides of the parallelogram are equal.
AB = CD ... (2)
Subtract (1) from (2):
AB - AE = CD - CF
BE = DF ... (3)
Also, BE is parallel to DF, therefore BEDF is a parallelogram.
Thus ED is parallel to BF.
Answered by | 17th Nov, 2013, 09:41: PM
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