CBSE Class 10 Answered
in a given rect ABCD find the
length of segments AQ and AP.
AQ is on CD and AP is on CB.
angle AQD = 30 and angle
APB=30. AD=30cm and AB= 60cm
find AP+AQ.
Asked by | 30 Jun, 2011, 10:54: PM
Expert Answer
In triangle ADQ, ADQ = 90o
In triangle ABP, ABP = 90o
Hence , AP + AQ = 120 + 60 = 180 cm
Answered by | 01 Jul, 2011, 12:06: PM
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