in a given rect ABCD find the length of segments AQ and AP. AQ is on CD and AP is on CB. angle AQD = 30 and angle APB=30. AD=30cm and AB= 60cm find AP+AQ.
Asked by | 30th Jun, 2011, 10:54: PM
Expert Answer:
In triangle ADQ, 
ADQ = 90o
In triangle ABP, ABP = 90o
Hence , AP + AQ = 120 + 60 = 180 cm
In triangle ADQ, ADQ = 90oABP = 90oAnswered by | 1st Jul, 2011, 12:06: PM
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