In a game, a man wins a rupee for a six and loses a rupee for any other number when a fair die is thrown. The man decided to throw a die thrice but to quit as and when he gets a six. Find the expected value of the amount he wins/loses. If he does not get a six in the first throw and gets a six in the second throw, then probability = Amount he will receive = ?Re 1 + Re 1 = 0

Asked by prabhakar p | 17th Mar, 2013, 06:15: PM

Expert Answer:

We need to consider the fourth case even where he does not get a 6 in any of his throws. 
Please note the answer in the book is wrong as that can be derived only by not considering this 4th case. 

Answered by  | 17th Mar, 2013, 06:46: PM

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