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Dear student

 

Take note the following diagram.

 

At point A

S = +3 m

Initial vel = +u

Final velocity: -v₂

Using v²-u² =2aS

we get the equation,

v₂² =u²-6g

 

At point B

S =-3m

Initial vel = +u

Final velocity = -v₁

Using v²-u² =2aS

we get the equation,

4v₂² =u² + 6g

substituting for v₁=2v₂ and solving for u we get

u = 10m/s

 

Then applying v²-u² =2aS along the path O' till O

we get

0-100 = -2gh

where h = max ht attained = 5m.

 

We hope that resolves your query.

 

Regards

 

Team

TopperLearning